If a particle of charge `10^(-12)` coulomb moving along the`hat(x)`-direction with a velocity `10^(5)m//s` experiences a force of `10^(-10)` newton in `hat(y)`-direction due to magnetic field. Then the minimum magnetic field is

Options

A. `5 xx 10^(-3)Wb//m^(2)`
B. `10^(-5)Wb//m^(2)`
C. `2 xx 10^(-3)Wb//m^(2)`
D. `10^(-3)Wb//m^(2)`

Answer

D

Explanation

`F=qvBsin theta therefore B=F/(qv sin theta)` Where theta is the angle between `vecv and vecB` B is minimum is `sin theta=1 or theta=90^(@)` therefore B is along Z axis. Minimum `B=F/(qv)=(10^(-10))/(10^(-12) xx 10^(5))=10^(-3)Wb//m^(2)`