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A straight section PQ of a circuit lise ...

A straight section `PQ` of a circuit lise along the `X`-axis from `x=-a/2` to `x=a/2` and carriers a steady current `i`. The magnetic field due to the section `PQ` at a point `X=+a` will be

A

proportional to l/a

B

zero

C

proportional to a

D

proportional to `a^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

The point R is at a distance x=a. Hence the magnetic field at P due to the section PQ of the circuit will be zero because the magnetic field at a point on the axis of a current carrying is zero.
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