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An electron is moving with the velocity of `10^(7)m/s`, parallel to a straight wire, carrying a current of 10 A. What is the force acting on the electron, if the electron is at a distance of 4 cm from the wire ?

A

`8 xx 10^(-17)N`

B

`6 xx 10^(-16)N`

C

`5 xx 10^(-17)N`

D

`3 xx 10^(-17)N`

Text Solution

Verified by Experts

The correct Answer is:
A

`B=(mu_0I)/(2pir)=(4pi xx 10^(-7) xx 10)/(2pi xx 4 xx 10^(-2))=5 xx 10^(-5)Wb//m^(2) therefore F=qvB=1.6 xx 10^(-19) xx 10^(7) xx 5 xx 10^(5)=8 xx 10^(-17)N`
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