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A wire of length l carries a steady current. It is bent first to form a circular plane loop of one turn. The magnetic field at the centre of the loop is B. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same is

A

unaltered

B

half of its value

C

double of its first value

D

four times of its first value

Text Solution

Verified by Experts

The correct Answer is:
D

`r_1=L/(2pi),r_2=(L/2)/(2pi)=L/(4pi) therefore r_2=R_1/2 but B=(mu_0)/(4pi)((2piI)/r)i.e Bpropto 1/r therefore` When r is reduced to half, the field becomes double and for 2 turns it will be 4B.
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