A coil of a moving coil galvanometer has 100 turns and effective area of` 0.005 m^(2)`. It is suspended in a radial magnetic field of induction` 0.001 Wb//m^(2)`. The torque per unit twist of thr suspension fibre is `5 xx 10^(-9)Nm`/degree. What is the currebnt sectivity of the moving coil galvanometer?

Options

A. `10^(5)` degree/ampere
B. `10^(7)` degrees/ampere
C. `2 xx 10^(6)` degrees/ampere
D. `3 xx 10^(5) ` degrees/ampere

Answer

B

Explanation

`I=(Ktheta)/(nAB) therefore C.S. =theta/1=(nAB)/K =(100 xx 5 xx 10^(-2)x 10^(-2))/(5xx10^(-9))=10^(7)`degree/ampere