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A galvanometer having a resistance of 18...

A galvanometer having a resistance of` 18 Omega `is shunted by a wire of resistance `2 Omega`. If the total current to be passed is 2A, then the part of it passing through the shunt will be

A

`0.8 A`

B

`1.5 A`

C

`1.8 A`

D

`1.25A`

Text Solution

Verified by Experts

The correct Answer is:
C
`I_s=G/(S+G)I=18/20x2=1.8 A`
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