In a ammeter `0.2%` of main current passes through the galvanometer. If resistance of galvanometer is `G`, the resistance of ammeter will be

Options

A. `1/500 G`
B. `500/499 G`
C. `1/499 G`
D. `499/500 G`

Answer

A

Explanation

`R=(GS)/(G+S)=((GS)/(S+G))xx1/G=R/G therefore 2/(10 xx 100)=R/G therefore R=G/(500)`