A particle having a charge 100 times that of an electron is revolution in a circular path of radius 0.4 m, with 1 rev/s. What is the magnitude of the magnetic field produced at its center?

Options

A. `10^(-7)mu_0`
B. `10^(-17)mu_0`
C. `2 xx 10^(-17)mu_0`
D. `2 xx 10^(-15)mu_0`

Answer

C

Explanation

Current `I=q/t=(100xx 1.6 xx 10^(-19))/1=1.6 xx 10^(-17)A therefore B=(mu_0I)/(2r)=(mu_0 xx 1.6 xx 10^(-17))/(2 xx 0.4)=2 xx 10^(-17)mu_0`.