A cyclotron of radius 64 cm accelerates deuterons. If the cyctron frequency is` 5 xx 10^(6) Hz`, then the maximum speed with which the deuterons emerge will be

Options

A. `2 xx 10^(6) m/s`
B. `3 xx 10^(7) m/s`
C. `2 xx 10^(7) m/s`
D. `3 xx 10^(6) m/s`

Answer

C

Explanation

`(mv)^(2)/r=qBv therefore v=(Bqr)/m` but `v=romega=2pifr=(Bqr)/m therefore (Bq)/m=2pif therefore v=2pifr-=2 xx 10^(7)m/s`