A bullet of mass `2 gm` is having a charge of `2 muc`. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of `10 m//s`

Options

A. `50 V`
B. `500 V`
C. `50 kV`
D. `5 kV`

Answer

C

Explanation

K.E. of the the bullet=Work done qV `therefore 1/2mv^(2)=qV therefore V+(mv^(2))/(2q)=(2 xx 10^(-3) xx 10 xx 10)/(2 xx 2 xx 10^(-6)) therefore V=50 xx 10^(3)V=50 kV`.