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An electron moves in a circular orbit wi...

An electron moves in a circular orbit with a uniform speed `v`.It produces a magnetic field `B` at the centre of the circle. The radius of the circle is proportional to

A

`B/v`

B

`v/B`

C

`sqrtB/v`

D

`sqrtv/B`

Text Solution

Verified by Experts

The correct Answer is:
D

A moving electron is equivilent to a current.`therefore I=(d_q)/(d_t)=e/T` The time taken by the electron to describe a circular path of radius r is `T=(2pir)/v therefore I=e/T=(e/(2pir))/v=(ev)/(2pir)therefore` The magnetic field at the center `B=(mu_0)/(4pi)((2piI)/r)therefore B=(mu_0)/(4pi).2pi.(ev)/(2pir)x1/r=(mu_0ev)/(4pir^(2))=K(v/r^(2))`where `K=(mu_0re)/(4pi)` is a constant `therefore r^(2)=(Kv)/B therefore r proptosqrtv/B`.
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