A particle of charge q and mass m, is fired perpenducular to a magnetic field (B) with a velocity v. What is the frequency of revolution of the particle?

Options

A. `(2pi)/(Bq)`
B. `(2piBq)/m`
C. `(2pim)/(Bq)`
D. `(Bq)/(2pim)`

Answer

D

Explanation

`(mv^(2))/r=qvB therefore v=(qBr)/m` it describes a circular path. `therefore T=("Distance")/(Velocity)=(2pirm)/(qBr)=(2pim)/(qB)therefore n=1/T=(qB)/(2pim)`.