The senstivity of a moving coil galvanometer is 'S'. If a shunt of `(1/8)th` of the resistance of the galvanometer is connected to the moving coil galvanometer, its senstivity becomes

Options

A. `S/3`
B. `S/6`
C. `S/9`
D. `S/12`

Answer

C

Explanation

Given: `Shunt S=G/8 and if 1^(th)/n` of the total current is to be passed through G, then `S=G/(n-1) therefore G/8=G/(n-1)therefore 8=n-1 therefore n=9` Since the range of the galvanometer is increased to `n=9` times, the senstivity is decreased to `1^(th)/9 or S'=S/9`.