Energy of the electron in `nth` orbit of hydrogen atom is given by `E_(n) =-(13.6)/(n^(2))eV`. The amount of energy needed to transfer electron from first orbit to third orbit is

Options

A. 1.51eV
B. 3.4eV
C. 13.6eV
D. 12.09eV

Answer

D

Explanation

`En=(-13.6)/(n^2) therefore E_1 -E_3 = -13.6 {(1)/(3^2) - (1)/(1^2)}`
`=13.6xx8/9 = 12.09eV`