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The energy of electron in an excited hyd...

The energy of electron in an excited hydrogen atom is `-3.4eV`. Its angular momentum according to bohr's theory will be

A

`(nh)/(2pi)`

B

`h/pi`

C

`(3h)/(2pi)`

D

`(2pi)/(h)`

Text Solution

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The correct Answer is:
B
`-3.4 = (-13.6)/(n^2) therefore n^2 = 4` and n = 2
`therefore " Angular momentum " = (nh)/(2pi)=(2h)/(2pi) = h/pi`
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