The area of the electron orbit for the ground state of hydrogen atom is A.What will be the area of the electron orbit corresponding to the first excited state ?

Options

A. `4:1`
B. `2:1`
C. `16:1`
D. `8:1`

Answer

C

Explanation

For the first excited state, n=2 and `r_2 = 4r_1`
Area `=pir_2^2 = pi . (16 r_1^2)`
`therefore A_2/A_1 = (16pir_1^2)/(pir_1^2)` = 16