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As par Bohr model, the minimum energy (i...

As par Bohr model, the minimum energy (in `eV`) required to remove an electron from the ground state of doubly ionized `Li` atom `(Z = 3)` is

A

40.8

B

13.6

C

122.4

D

1.51

Text Solution

Verified by Experts

The correct Answer is:
A
`E_n = -13.6 Z^2/n^2 eV`
For n=1 and Z=3 , we get
`E=-Z^2 xx13.6=-9xx13.6=-122.4 eV`
`therefore` Ionisation energy =+122.4 eV
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