For an electron moving in `n^(th)` orbit of H-atom the angular velocity is proportional to

Options

A. `1/n`
B. `n^3`
C. `1/n^3`
D. `n`

Answer

C

Explanation

For an electron moving in the nth orbit
`v_n prop 1/n " and " r_n prop n^2`
`therefore omega_n = v_n/r_n prop (1)/(n.n^2) prop 1/n^3`
Thus `omega_n prop 1/n^3`