when a hydrogen atom is raised from the ground state to an excited state

Options

A. Both K.E. and P.E. decrease
B. P.E. increases and K.E. decreases
C. Emission spectrum is produced
D. P.E. decreases and K.E. increases

Answer

B

Explanation

For the hydrogen atom , K.E. `= (Ke^2)/(2r)`
and P.E. `= - (Ke^2)/(r )`
When the atom is raised from the ground state to an excited state , r increases.
`therefore` K.E. decreases.
P.E. decreases numerically but because of the -ve sign, it increases .
Thus P.E. increases and K.E. decreases