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Energy required for the electron excitat...

Energy required for the electron excitation in `Li^(++)` from the first to the third Bohr orbit is:

A

12.1 eV

B

36.3 eV

C

108.8 eV

D

122.4 eV

Text Solution

Verified by Experts

The correct Answer is:
C
`E_n = - ((13.6Z^2)/(n^2)) eV` for an atom
For Lithium `Li^(++) , Z=3`
`therefore E_n = - (13.6xx9)/(n^2)`
`therefore E_1 = - (13.6xx9)/(1^2) = - 122.4 eV`
and `E_3 = - (13.6xx9)/(9) = - 13.6 eV`
`therefore Delta E = E_3 - E_1 = -13.6 - (-122.4) eV = 108.8 eV`
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