The ratio of minimum to maximum wavelength in Balmer series is

Options

A. `4:1`
B. `9:5`
C. `36:5`
D. `4:3`

Answer

B

Explanation

For Balmer series , Longest wavelength corresponds to
`n_i = 3 " and " n_f = 2 " and " lamda_B = (36)/(5R)`
for shortest wavelength `n_i = oo " and " lamda'_B = 4/R`
`therefore (lamda_B)/(lamda_B') = (36)/(5R) xx R/4 = 9/5`