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The follwing diagram indicates the energy levels of a certain atom when the system moves from `2E` level to `E`, a photon of wavelength `lambda` is emitted. The wavelength of photon produced during its transition from `(4E)/(3)` level to `E` is

A

`(4lamda)/(3)`

B

`3lamda`

C

`lamda/3`

D

`(3lamda)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
`2E-E=hv = (hc)/(lamda) therefore E = (hc)/(lamda)`
and `(4E)/(3) - E = E/3 = (hc)/(lamda')`
`therefore lamda' = (3hc)/(E ) = (3hc)/((hc)/(lamda)) = 3lamda`
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