The force of repulsion between two electrons kept at a distance of 1 m is F. if m is the mass of the electron, h is the planck's constant and c is the velocity of light, then the Rydberg's constant of

Options

A. `(F^22pi^2m)/(h^3C)`
B. `(F2pi^2m)/(h^3C)`
C. `(h^3C)/(F^2 2pi^2m)`
D. `(F2pi^2m)/(h^2C)`

Answer

A

Explanation

Rydberg's constant ,` R=(me^4)/(8epsi_0^2 Ch^3)`
and `F= (1)/(4piepsi_0) (e^2)/(1^2) therefore r= 1`
`therefore F^2 = (e^4)/( 16 pi^2 epsi_0^2)`
From the given options (a) is the correct option as
`therefore (F^2. 2pi^2m)/(Ch^3) = (e^4)/(16pi^2 epsi_0^2) xx (2pi^2m)/(Ch^3)`
`= (me^4)/(8epsi_0^2Ch^3) = R`