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A proton and an alpha - particle are acc...

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

A

`2sqrt(2):1`

B

`1:sqrt2`

C

`sqrt(2) : 1`

D

`1:2sqrt2`

Text Solution

Verified by Experts

`lamda = (h)/(mv) = (h)/(sqrt(2mqv))`
For same V, `lamda prop 1/(sqrt(mq))`
`therefore lamda_P/lamda_alpha = sqrt((m_alpha q _alpha)/(m_P q_P)) = sqrt(4/1xx2/1) = 2sqrt2`
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