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If the kinetic energy of a free electron...

If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factor

A

2

B

`1/2`

C

`sqrt2`

D

`1/sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
D
`lamda= (h)/(sqrt(2mE)) ' lamda prop 1/sqrtE`
`therefore lamda_2/lamda_1 = sqrt(E_1/E_2) = sqrt(1/2) = 1/sqrt2`
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