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A potential difference of 15 KV is appli...

A potential difference of 15 KV is applied to accelerate the electron in an electron microscope. The de broglie wavelength of the electron waves is

A

1 Å

B

0.1 Å

C

0.5 Å

D

0.01 Å

Text Solution

Verified by Experts

The correct Answer is:
B
`lamda = sqrt(150/V) = sqrt(150/15000) = 0.1 Å`
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