The circumference of the third Bohr orbit of an electron is `4.5xx10^(-9) m` . What is the de broglie wavelength of the electron in this orbit ?

Options

A. `1.5xx10^(-9) m`
B. `3xx10^(-9) m`
C. `4.5xx10^(-9) m`
D. `6xx10^(-9) m`

Answer

A

Explanation

For an electron , `mvr = (nh)/(2pi)`
`therefore 2pir = (nh)/(mv) = nlamda (therefore lamda = (h)/(mv))`
`therefore lamda = (2pir)/(h) = (4.5xx10^(-9))/(3) = 1.5xx10^(-9) m`