If the de broglie wavelength of a particle is decreased, what will happen to its momentum (p) and K.E. (K) ?

Options

A. Both will decrease
B. Both p and K will increase
C. K will increase, p will decrease
D. K will decrease , p will increase

Answer

B

Explanation

`lamda = h/P therefore P = h/lamda`
`therefore " If " lamda` is decreased , p wil increase
and `therefore lamda = (h)/(sqrt(2mK)) , ` K will increase