Write the expression for the de-Broglie wavelength associated with a charged particle having charge 'q' and mass 'm' when it is accelerated by a potential V.

Options

A. `(h)/(sqrt(2mqV))`
B. `(h^2)/(sqrt(2mqV))`
C. `(h)/(sqrt(mqV))`
D. `(h)/(sqrt(2qV))`

Answer

A

Explanation

De broglie wavelength `lamda = (h)/(mv) = (h)/(sqrt(2mE)) " " … (1)`
where E is the K.E. of the electron. If a particle of mass m and change q is accelerated through a P.D. (v), then K.E. = work done `=qV [ V = W/q]`
`therefore E = qV`
`therefore "from (1) , " lamda = (h)/(sqrt(2mE)) = (h)/(sqrt(2mqV))`