An X - ray tube with a copper target emits `K_alpha` line of copper of wavelength 1.5 Å. What should be the minimum voltage through which the electrons should be accelerated to produce this wavelength of X rays ?

Options

A. a) 8.28 V
B. b) 828 V
C. c) 8280 V
D. d) 82800 V

Answer

C

Explanation

`because V = W/q = W/e = (hv)/(e ) = (hc)/(lamda.e)`
`therefore V = (6.63xx10^(-34)xx3xx10^8)/(1.5xx10^(-10)xx1.6xx10^(-19))`
` = (6.63xx2)/(1.6) xx 10^3 = 8287 = 8280 V`