The mass number of He is `4` and that for suphur is `32`. The radius of sulphur nuclei is larger than that of helium by

Options

A. 3
B. 4
C. 5
D. 2

Answer

D

Explanation

Radius of nucleus ` prop A^(1//3)` where A its mass number. For sulphur A = 32 , for helium A = 4
`therefore (R_S)/(R_(He)) = ((A_(S))/(A_(He)))^(1//3) = (32/4)^(1//3) = 2`