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In the nuclear raction given by .2He^4 ...

In the nuclear raction given by `._2He^4 +._7N^(14) rarr ._1H^1 +X` the nucleus X is

A

`""_7N^16`

B

`""_7O^16`

C

`""_7N^17`

D

`""_8O^17`

Text Solution

Verified by Experts

The correct Answer is:
D

`""_7H^14 + ""_2He^4 to ""_1H^1 + X`
Z for X, 7+2-1=8
A for X, 14+4-1=17
`therefore` Z is given by `""_8O^17`
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