When `_(3)Li^(7)` nuclei are bombarded by protons , and the resultant nuclei are `_(4)Be^(8)` , the emitted particle will be

Options

A. Beta particles
B. Gamma particles
C. Alpha particles
D. Neutron

Answer

B

Explanation

The given nuclear reaction is `""_3Li^7 + ""_1H^1 to ""_4Be^8 + ""_ZX^A`
where X is the emitted particle having atomic no. Z and atomic mass A
For X, Z= (3+1) - 4 = 0
A = (7+1) - 8 =0
Thus X has zero charge and zero mass.
`therefore` it is a gamma photon .
For neutrons Z =0 but A = 1, for `beta` particles A = 0 but Z = -1 , for `alpha` particles Z = 2 and A = 4