If radius of the `._13^27 A1` nucleus is taken to be `R_(A1)` then the radius of `._53^125 Te` nucleus is nearly.

Options

A. `5/3 R_(Al)`
B. `3/5R_(Al)`
C. `(13/53)^(1//3) R_(Al)`
D. `(53/13)^(1//3) R_(Al)`

Answer

A

Explanation

Nuclear radius `(R ) prop A^(1//3)`
`therefore (R_(Te))/(R_(Al)) = (125/27)^(1//3) = 5/3`
`therefore R_(Te) = 5/3 Al`