Consider the nuclear reaction `X^200 to A^110 + B^80` . The binding energy per nucleon for X, A and B are 7.4 MeV, 8.2 MeV and 8.1 MeV respectively. What is the energy released in the nuclear reaction ?

Options

A. a) 380 MeV
B. b) 190 MeV
C. c) 100 MeV
D. d) 70 MeV

Answer

D

Explanation

For the element X,
Binding enery = `200xx7.4 =1480 MeV`
For A, binding energy `=110xx8.2 = 902 MeV`
For B, binding energy `=80xx8.1 = 648 MeV`
`therefore` Energy released in the reaction
`=(902 + 648) - 1480 = 1550 - 1480 = 70 MeV`