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The mass defect for the nucleus of heliu...

The mass defect for the nucleus of helium is `0.0303` a.m.u. What is the binding energy per nucleon for helium in `MeV` ?

A

1

B

28

C

7

D

4

Text Solution

Verified by Experts

The correct Answer is:
C

The binding energy of a nucleus is also defined as the energy equivalent of the mass defect of the nucleus ` = (Deltam)c^2`
`therefore ("Binding energy ")/("Nucleon") = ("mass defect" (Deltam) xxc^2)/("No. of nucleon (A)")`
`= (0.0303xx931)/(4) = 7 MeV`
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