If `M_(o)` is the mass of an oxygen isotope `._(8)O^(17), M_(p)` and `M_(N)` are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is:

Options

A. `M_0C^2`
B. `(M_0-8M_p) C^2`
C. `(M_0 - 17 M_N)C^2`
D. `(M_0 - 8 M_p - 9 M_N)C^2`

Answer

D

Explanation

The oxygen isotopes `""_8O^17` contains 8 protons and 9 neutrons.
`therefore` Mass of oxygen isotopes nucleus = `8M_P + 9 M_N`
The mass defect of nucleus `(Deltam)`
= Mass of nucleus - Mass of isotopes nucleus
`therefore Deltam = M_0 - 8 M_P - 9 M_N`
`therefore` Binding energy = mass defect `xxC^2`
`therefore B.E. = (M_0 - 8M_P - 9M_N) C^2`