When `._92 U^235` undergoes fission, `0.1 %` of its original mass is changed into energy. How much energy is released if `1 kg` of `._92 U^235` undergoes fission ?

Options

A. `9xx10^12 J`
B. `9xx10^10 J`
C. `9xx10^13 J`
D. `9xx10^11 J`

Answer

C

Explanation

`E=(Deltam)c^2`
In this case, `Delta m = (0.1)/(100) xx1 = 10^(-3) Kg`
`therefore E = (Delta m )c^2 = 10^(-3) xx (3xx 10^8)^2 = 9 xx 10^13 J`