Energy released in the fission of a single `""_92U^235` nucleus is 200 MeV . What is the fission rate of a `""_92U^235` filled nuclear reactor operating at a power level of 500 MW ?

Options

A. a) `1.56xx10^(-17)s^(-1)`
B. b) `1.56xx10^19 s^(-1)`
C. c) `1.56xx10^16 s^(-1)`
D. d) `1.56xx10^(-10) s^(-1)`

Answer

B

Explanation

Total power of the nuclear reactor
`= 500 MW = 500xx 10^6 W`
Energy released per fission `= 200MeV = 200 xx 10^6 eV`
`= 200 xx 10^6 xx 1.6 xx 10^(-19) J`
`=320 xx 10^(-13) J`
`therefore` Fission rate `= (" Nuclear power")/("Energy produced /Fission" )`
`= (500xx10^6)/(320 xx 10^(-13)) = 1.56xx 10^(19)` / second