A nucleus `""_ZX^A " emits " 6 alpha " particles and " 4 beta` particles is converted into `""_(Z')X_2^(A')` . What is the ratio of the total number of proton and neutrons in `""_(Z')X_2^(A')` ?

Options

A. `(Z-10)/(A-Z-8)`
B. `(Z-8)/(A-Z-16)`
C. `(Z-12)/(A-Z-10)`
D. `(Z-6)/(A-Z-18)`

Answer

B

Explanation

`""_Z X^A overset(6alpha)(to) ""_(Z-12)X_1^(A-24) overset(4beta)(to) ""_(Z-8)X_2^(A-24)`
`therefore " For " X_2` , no. of protons = Z - 8
and number of neutrons = (A-24) - (Z-8) = A -Z -16
`therefore (n_P)/(n_N) = (Z-8)/(A-Z-16)`