The half life of radioactive substance is `1.1xx10^7` s. What is the decay rate for `4.4xx10^15` atoms of the substance ?

Options

A. `2.2xx10^9` atoms/s
B. `2.77xx10^8` atoms/s
C. `4.6 xx10^9` atoms/s
D. `4.6xx10^7` atoms/s

Answer

B

Explanation

Given : `T = 1.1xx10^7` s
and `T = (0.693)/(lamda) therefore lamda = (0.693)/(T)`
`therefore (dN)/(dt) = - lamdaN`
Or `(dN)/(dt) = |(0.693)/(1.1xx10^7)xxN|`
`= (0.693)/(1.1xx10^7) xx 4.4 xx 10^15`
`=4xx0.693xx10^8 = 2.77xx10^8` atoms/s