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Mean life of a radioactive sample is 100...

Mean life of a radioactive sample is 100s . Then ,its half-life (in min) is

A

0.693 min

B

`10^(-4)` min

C

1.155 min

D

1 min

Text Solution

Verified by Experts

The correct Answer is:
C
`tau = " mean life " = 1/lamda`
`therefore " half life " , T = (0.693)/(lamda) = 0.693xx tau -0.693xx100`
`= 69.3 s = (69.3)/(60) = 1.155` min.
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