The fossil bone has a `.^(14)C` : `.^(12)C` ratio, which is `[(1)/(16)]` of that in a living animal bone. If the half -life of `.^(14)C` is `5730` years, then the age of the fossil bone is :

Options

A. 17190 years
B. 22920 years
C. 45840 years
D. 11460 years

Answer

B, D

Explanation

This is based on carbon dating
To have the ratio 1:16 , we have `(N/N_0) = (1/2)^n`
`therefore (1/16) = (1/2)^n therefore n= 4` = no. of half lives.
`therefore` Age of fossile bone `=4xx " half life "`
=`4xx5730 = 22920` years