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The half-life of .^215At is 100mus. The ...

The half-life of `.^215At` is `100mus`. The time taken for the activity of a sample of `.^215At` to decay to `1/16th` of its initial value is

A

`400mus`

B

`300mus`

C

`40mus`

D

`6.3mus`

Text Solution

Verified by Experts

The correct Answer is:
C
`N/N_0 = (1/2)^n therefore N/N_0 = 1/16 = (1/2)^4`
`therefore n =4`
`therefore` Time taken = n x half life `=(4xx100) = 400 mus`
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