Half-life period of a radioactive substance is `6 h`. After `24 h` activity is `0.01 muC`, what was the initial activity ?

Options

A. `0.16muC`
B. `0.08muC`
C. `0.04muC`
D. `0.24muC`

Answer

A

Explanation

Activity `A = A_0 (1/2)^n = A_0 (1/2)^(t/T) = A_0 (1/2)^(24/6)`
in this case ,A = 0.01 microcurie
`therefore 0.01 = A_0 (1/16) therefore A_0 = 16xx0.01 = 0.16 mu C`