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The half - line period a radioactive ele...

The half - line period a radioactive element `X` is same as the mean life time of another radioactive element `Y`. Initially both of them have the same number of atoms. Then:

A

Y will decay at a faster rate than X

B

X will decay at a faster rate than Y

C

X and Y always decay at the same rate

D

X and Y have the same decay rate initially

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Verified by Experts

The correct Answer is:
A

Given : `T(_("half") )_X = (tau_("mean"))_Y`
`(0.693)/(lamda_X) = (1)/(lamda_Y) therefore lamda_X = 0.693 lamda_Y`
Thus `lamda_Y gt lamda_X`
Initially both X and Y have the same number of atoms but `therefore lamda_Y gt lamda_X` , Y will decay at a faster rate than X.
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