What is the de broglie wavelength of an electron moving with 1/3 of the speed of light in vaccum ? (Neglect the relativistic effect )
`[h=6.63xx10^(-34) J.s (M_e=9.11xx10^(-28) g)]`

Options

A. a. `7.278xx10^(-12) m`
B. b. `6.782 xx10^(-11) m`
C. c. `8.532xx10^(-11) m`
D. d. `9.728xx10^(-12) m`

Answer

A

Explanation

`v=C/3 = (3xx10^8)/(3) = 10^8 m//s`
and `m_e = 9.11xx10^(-28) g = 9.11 xx 10^(-31) kg`
`therefore lamda = (h)/(mv) = (6.63xx10^(-34))/(9.11xx10^(-31)xx10^8)`
`=(6.63xx10^(-11))/(9.11)`
`=7.728xx10^(-12) m`