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The velocity of an electron in the first...

The velocity of an electron in the first Bohr orbit of hydrogen atom is `2.19 xx 10^(6)ms^(-1)`. Its velocity in the second orbit would be

A

`1.1xx10^6` m/s

B

`4.4xx10^6` m/s

C

`sqrt(2.2xx10^6)` m/s

D

`1.1xx10^3` m/s

Text Solution

Verified by Experts

The correct Answer is:
A
Orbital velocity `prop 1/n " " v_2/v_1 = n_1/n_2 = 1/2`
`therefore v_2 = (v_1)/(2) = 1.1xx10^6 m//s`
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