The radius of the orbital of electron in the hydrogen atom `0.5 Å`. The speed of the electron is `2 xx 10^(6)m//s`. Then the current in the loop due to the motion of the electron is

Options

A. 2 mA
B. 3 mA
C. 1 mA
D. `4xx10^(-3) A`

Answer

C

Explanation

`I=q/T = (q)/((2pir)/(v)) = (qv)/(2pir)`
`therefore I = (1.6xx10^(-19) xx 2 xx 10^6)/(2xx 3.14xx 0.5 xx 10^(-10)) = 1mA`