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What will be the ratio of de - Broglie w...

What will be the ratio of de - Broglie wavelengths of proton and `alpha` - particle of same energy ?

A

`1:2`

B

`1:4`

C

`2:1`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`(lamda_p)/(lamda_alpha) = sqrt((2m_alpha E)/(em_p E )) = sqrt(4/1) = 2/1`
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